# ListFunctions3(A, B, C)¶

map(fn, list1, u2) applies the binary function fn to corresponding elements of lists u1 and u2 and returns a list of the results (in the same order). Thus map(/, [1, 2, 3], [4, 5, 6]) = [1/4, 2/4, 1/2]. The computation terminates when the end of either list is reached. That is, the length of the result list is equal to the minimum of the lengths of u1 and u2.